To solve the equation x^n + y^n = z^n in C#, we can use a brute force approach to check all possible values of x, y, and z within a given range. However, it's important to note that this equation is a special case of Fermat's Last Theorem, which states that there are no whole number solutions to the equation a^n + b^n = c^n for n > 2.
Therefore, we cannot find integer solutions for this equation using our typical numerical methods. Instead, we can implement an algorithm that searches for a counter-example to the theorem, which was famously proven by Andrew Wiles in 1994.
In C#, we can write an implementation of this algorithm as follows:
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This program sets n = 3, and then checks all possible values of x, y, and z up to 100 for a counter-example to the theorem. If a solution is found, the program will print the values of x, y, and z that satisfy the equation.
However, as previously noted, we know that there are no integer solutions to this equation for n > 2. Therefore, this program will not be able to find a solution and will return "No counter-example found - Fermat's Last Theorem is true!".
Note: In order to find numerical solutions to the equation x^n + y^n = z^n for n > 2, we must use more advanced mathematical techniques, such as elliptic curves or modular forms, which are beyond the scope of this answer.
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