To find the area bounded by f(x)=9-x^2 and g(x)=x-3, you must first find the x-coordinates of points where they intersect. This can be done by setting the two functions equal to each other and solving for x:
9 - x^2 = x - 3
x^2 + x - 6 = 0
(x + 3)(x - 2) = 0
x = -3, 2
Now, we can integrate to find the area between the curves. Since f(x) is on top and g(x) is on the bottom,
Area = ∫[a,b] (f(x) - g(x)) dx = ∫[-3,2] (9 - x^2 - (x - 3)) dx
Area = ∫[-3,2] (12 - x^2 - x) dx
Area = [12x - (x^3/3) - (x^2/2)] from -3 to 2
Area = 65.5
Therefore, the area bounded by f(x)=9-x^2 and g(x)=x-3 is 65.5 square units.
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