routing http server in python in javascript

To implement routing in a http server in Python, you can use the http.server module which comes with Python 3.0 and higher. Specifically, you can create a subclass of the http.server.BaseHTTPRequestHandler and override the do_GET() method to handle incoming GET requests.

Here's an example implementation of a simple HTTP server that routes to different pages based on the path:


main.py
import http.server
import socketserver

class RequestHandler(http.server.BaseHTTPRequestHandler):
    def do_GET(self):
        if self.path == '/':
            self.send_response(200)
            self.send_header('Content-type', 'text/html')
            self.end_headers()
            self.wfile.write(b'<html><body><h1>Welcome!</h1></body></html>')
        elif self.path == '/about':
            self.send_response(200)
            self.send_header('Content-type', 'text/html')
            self.end_headers()
            self.wfile.write(b'<html><body><h1>About us</h1><p>We are a group of coders.</p></body></html>')
        else:
            self.send_error(404)

PORT = 8000

handler = socketserver.TCPServer(("", PORT), RequestHandler)
print("serving at port", PORT)
handler.serve_forever()
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This will start a HTTP server that listens on port 8000. When a GET request is received, it checks the path and sends a response accordingly. For example, a request to http://localhost:8000/about will return the "About us" page.

To interact with this server using JavaScript, you can use the XMLHttpRequest or fetch() APIs to send HTTP requests and receive responses asynchronously. Here's an example using fetch():


index.tsx
fetch('http://localhost:8000/about')
  .then(response => response.text())
  .then(text => console.log(text))
  .catch(error => console.error(error));
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This will fetch the "About us" page from the server and log its contents to the console.

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