write a program which uses a function to test if a given year is a leap year. your function should return a value of 0 if it is true that the year is a leap year and a value of 1 if it is false. in javascript

index.tsx
function isLeapYear(year) {
  if (year % 4 == 0) {
    if (year % 100 == 0) {
      if (year % 400 == 0) {
        return 0;
      } else {
        return 1;
      }
    } else {
      return 0;
    }
  } else {
    return 1;
  }
}

// Example Usage
console.log(isLeapYear(2000)); // 0
console.log(isLeapYear(2021)); // 1
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The isLeapYear function takes a year as its parameter and returns 0 if it is a leap year, and 1 if it is not.

The function works by first checking if the year is divisible by 4. If it is not, the function will immediately return 1, indicating that it is not a leap year.

If the year is divisible by 4, the function will then check if it is also divisible by 100. If it is, the function will check if it is also divisible by 400. If it is, the function will return 0, indicating that it is a leap year. If it is not divisible by 400, then the function will return 1, indicating that it is not a leap year.

If the year is divisible by 4 but not by 100, the function will return 0, indicating that it is a leap year. This is because any year that is divisible by 4 but not by 100 is a leap year, as long as it is not also divisible by 400.

The final console log statements show how to use the function.