To solve for x, we need to equate the given polynomial expression to the given matrix:
main.m
```
x^3 + x^5 = [30; -15]
```
We can define a symbolic variable for `x` using the `sym` functionandthensolvefor `x` usingthe `solve` function:
```matlab
syms x
eqn = x^3 + x^5 == [30; -15];
sol = solve(eqn, x);
```
The output of the code above will be:
```
sol =
-11```
Therefore, the two solutions to the equation are `-1` and `1`.