create a variable containing the sample name given a fast filename in python

To create a variable containing the sample name given a fast filename in Python, we need to extract the sample name from the filename. Assuming that the sample name is the part of the filename before the first underscore character, we can use the split() method to split the filename into a list and then get the first element of the list. Here's an example code that shows how to do this:

main.py
fastq_file = "sample_001.fastq"
sample_name = fastq_file.split("_")[0]
print(sample_name)  # output: "sample"
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In this code, we first create a variable fastq_file containing the filename "sample_001.fastq". We then use the split() method to split the filename into a list of strings using the underscore character as the separator, like this: fastq_file.split("_"). This gives us the list ["sample", "001.fastq"]. Finally, we get the first element of the list (index 0) using [0], and store it in the variable sample_name. The output of running this code is "sample".