find a white square bigger than 500 pixels and highlight it in python

You can achieve this using the OpenCV library in Python. Here's some sample code to get you started:

main.py
import cv2

# Load the image
img = cv2.imread("path/to/image.jpg")

# Convert the image to grayscale
gray = cv2.cvtColor(img, cv2.COLOR_BGR2GRAY)

# Find all white objects in the image (assuming white objects are already the brightest, so invert the image)
_, thresh = cv2.threshold(255-gray, 240, 255, cv2.THRESH_BINARY)

# Find contours in the image
contours, _ = cv2.findContours(thresh, cv2.RETR_LIST, cv2.CHAIN_APPROX_SIMPLE)

# Loop over all contours
for contour in contours:
    # Compute the bounding box of the contour
    x, y, w, h = cv2.boundingRect(contour)
    
    # Check if the bounding box meets the size criterion
    if w > 500 and h > 500:
        # Draw a green rectangle around the bounding box
        cv2.rectangle(img, (x,y), (x+w,y+h), (0, 255, 0), 2)

# Display the result
cv2.imshow("result", img)
cv2.waitKey(0)
842 chars
28 lines

This code loads an image, converts it to grayscale, and extracts all white objects using a simple thresholding operation. It then computes the bounding box of each white object and checks if it's bigger than 500x500 pixels. If so, it draws a green rectangle around the object's bounding box. Finally, it displays the result.

Note that the code assumes that white objects are already the brightest and that the image is relatively clean. If this is not the case, you may need to apply some pre-processing operations (such as noise reduction, adaptive thresholding, or morphological operations) to improve the accuracy of the white object extraction.

related categories

gistlibby LogSnag