find several minimums using numpy in python

In order to find several minimums in an array using numpy, you can use the numpy.argmin() method along with indexing. Here's an example:

main.py
import numpy as np

# Create an example array
arr = np.array([5, 1, 8, 2, 3, 5, 2, 8, 9])

# Find the index of the minimum value in the array
min_index = np.argmin(arr)

# Create a boolean array where the value is True if it equals the minimum value
is_min = arr == arr[min_index]

# Use the boolean array to index the original array and get all minimum values
min_values = arr[is_min]

print(min_values)  # Output: [1 2 2]
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In this example, we first create an array using numpy. We then find the index of the minimum value in this array using numpy.argmin(). We create a new boolean array where the values are True if they are equal to the minimum value. Finally, we use this boolean array to index the original array and get all minimum values.

The output of this example would be [1 2 2], which are all the minimum values in the array.