find two middle elements of a list with odd number elements in python

One way to find the two middle elements of a list with odd number of elements is using the floor division operator and list slicing. Here's an example code snippet that demonstrates this:

main.py
lst = [1, 2, 3, 4, 5, 6, 7]
mid = len(lst) // 2
middle_elements = lst[mid-1:mid+1]
print(middle_elements)  # Output: [3, 4]
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In the above code, we first find the index of the middle element by dividing the length of the list by 2 using the floor division operator //. We then use list slicing to extract the two middle elements by specifying the start and end index of the slice. Note that we subtract 1 from the mid index to get the left middle element and add 1 to get the right middle element.

If the list has an even number of elements, we can modify the code above slightly to return the two middle elements that are closest to the center. Here's an example:

main.py
lst = [1, 2, 3, 4, 5, 6]
mid = len(lst) // 2
middle_elements = lst[mid-1:mid+1] if len(lst)%2==0 else [lst[mid]]
print(middle_elements)  # Output: [3, 4]
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In the above code, we first check if the length of the list is even or odd using the modulus operator %. If it's odd, we use the mid index to directly extract the middle element. If it's even, we use the same list slicing technique as before to get the two middle elements.

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