give this as a list comprehension or a generic line: `square = lambda n: 2**(n-1) if n>=1 or n<=64 else valueerror("between 1 and 64")` in python

You can rewrite the given code using a list comprehension to generate a list of squares for a range of numbers. However, note that the code as provided is not correct, as the condition if n>=1 or n<=64 should be if n>=1 and n<=64 for the desired behavior.

Here's the corrected code as a list comprehension:

main.py
squares = [2**(n-1) for n in range(1, 65)]
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This will generate a list of squares of numbers ranging from 1 to 64.

If you specifically want a lambda function that computes the square for a given number, you can use the following code:

main.py
square = lambda n: 2**(n-1) if 1 <= n <= 64 else ValueError("Number should be between 1 and 64.")
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In this lambda function, if the number n is between 1 and 64 (both inclusive), it will calculate the square using the formula 2**(n-1). Otherwise, it will raise a ValueError with the given message.

Note that this lambda function will not give you a list of squares for a range of numbers like the list comprehension above. It will only calculate the square for a given number n.