create an example function that uses dynamic programming to sort a binary tree in ruby

Here's an example function in Ruby that uses dynamic programming to sort a binary tree:

main.rb
def sort_binary_tree(node)
  return node if node.nil? || (node.left.nil? && node.right.nil?)
  
  # Recursively sort the left and right sub-trees
  node.left = sort_binary_tree(node.left)
  node.right = sort_binary_tree(node.right)
  
  # Merge the left and right sub-trees
  if node.left.nil?
    return node.right
  elsif node.right.nil?
    return node.left
  else
    sorted = merge(node.left, node.right)
    return sorted
  end
end

# Merge two binary trees
def merge(a, b)
  if a.nil?
    return b
  elsif b.nil?
    return a
  elsif a.data < b.data
    a.right = merge(a.right, b)
    return a
  else
    b.right = merge(b.right, a)
    return b
  end
end
664 chars
33 lines

In this function, sort_binary_tree takes a binary tree as an argument and returns a sorted binary tree using dynamic programming. It recursively sorts the left and right sub-trees, and then merges the sorted sub-trees using the merge function.

The merge function merges two binary trees by recursively merging their right sub-trees, and then merging the larger sub-tree to the right of the smaller sub-tree. This ensures that the resulting binary tree is sorted.

Overall, this example demonstrates how dynamic programming can be used to efficiently sort a binary tree in Ruby.

gistlibby LogSnag