given a string representing a matrix of numbers, return the rows and columns of that matrix. in ruby

To return the rows and columns of a matrix given a string representation in Ruby, you can follow these steps:

  1. Split the string into an array of rows.
  2. Split each row into an array of numbers.
  3. Transpose the rows to get the columns.

Here's the code that accomplishes the above steps:

main.rb
def matrix_rows_columns(matrix_str)
  # Split the string into an array of rows
  rows = matrix_str.split("\n")

  # Split each row into an array of numbers
  matrix = rows.map { |row| row.split.map(&:to_i) }

  # Transpose the rows to get the columns
  columns = matrix.transpose

  # Return both the rows and columns
  [matrix, columns]
end
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You can use the above method by passing the string representation of the matrix to it. It will return an array containing both the rows and columns of the matrix.

Here's an example usage:

main.rb
matrix_str = "1 2 3\n4 5 6\n7 8 9"
rows, columns = matrix_rows_columns(matrix_str)

puts "Rows:"
rows.each { |row| puts row.join(" ") }

puts "Columns:"
columns.each { |column| puts column.join(" ") }
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This will output:

main.rb
Rows:
1 2 3
4 5 6
7 8 9
Columns:
1 4 7
2 5 8
3 6 9
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Make sure the string representation of the matrix follows the format specified in the example (numbers separated by spaces, rows separated by newlines).

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