how to iterate over each elements of "the quick brown fox jumps over the lazy dog" to check if they exist in [*'a'..'z']? ignore white space in ruby

To iterate over each element of the string "the quick brown fox jumps over the lazy dog" in Ruby and check if they exist in the range of lowercase letters from 'a' to 'z', you can use the each_char method to iterate through each character of the string. By ignoring white space, you can conditionally check if the character is present in the range using the include? method.

Here's an example:

main.rb
string = "the quick brown fox jumps over the lazy dog"

string.each_char do |char|
  next if char == ' ' # Ignore white space
  if ('a'..'z').include?(char)
    puts "#{char} exists in the range [a-z]"
  else
    puts "#{char} does not exist in the range [a-z]"
  end
end
272 chars
11 lines

In the above code, we iterate through each character of the string string. The next statement skips the iteration if the character is a white space. We then use the include? method to check if the character is present in the range 'a'..'z' (which represents all lowercase letters).

The output will display whether each character exists or does not exist in the range [a-z].

t exists in the range [a-z]
h exists in the range [a-z]
e exists in the range [a-z]
q exists in the range [a-z]
u exists in the range [a-z]
i exists in the range [a-z]
c exists in the range [a-z]
k exists in the range [a-z]
b exists in the range [a-z]
r exists in the range [a-z]
o exists in the range [a-z]
w exists in the range [a-z]
n exists in the range [a-z]
f exists in the range [a-z]
x exists in the range [a-z]
j exists in the range [a-z]
u exists in the range [a-z]
m exists in the range [a-z]
p exists in the range [a-z]
s exists in the range [a-z]
o exists in the range [a-z]
v exists in the range [a-z]
e exists in the range [a-z]
r exists in the range [a-z]
t exists in the range [a-z]
h exists in the range [a-z]
e exists in the range [a-z]
l exists in the range [a-z]
a exists in the range [a-z]
z exists in the range [a-z]
y exists in the range [a-z]
d exists in the range [a-z]
o exists in the range [a-z]
g exists in the range [a-z]
952 chars
35 lines

This code prints every character that exists in the range [a-z] while ignoring white spaces.

Remember to replace the puts statements with your desired logic or operations depending on what you want to achieve with the characters that exist or do not exist in the range.

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