find the variance of all nodes in a linked list in csharp

To find the variance of all nodes in a linked list in C#, we can follow these steps:

  1. Create the linked list with some nodes and a function to calculate the variance of the nodes.
main.cs
class Node 
{
    public int value;
    public Node next;
}

LinkedList<Node> list = new LinkedList<Node>();

double variance(LinkedList<Node> list) 
{
    double sumOfSquares = 0.0, mean = 0.0, variance;
    int count = 0;
    Node current = list.First;

    while (current != null) 
    {
        count++;
        mean += current.value;
        current = current.next;
    }

    mean /= count;
    current = list.First;

    while (current != null) 
    {
        sumOfSquares += Math.Pow(current.value - mean, 2);
        current = current.next;
    }

    variance = sumOfSquares / count;
    return variance;
}
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  1. Populate the linked list with some values:
main.cs
list.AddLast(new Node { value = 10 });
list.AddLast(new Node { value = 15 });
list.AddLast(new Node { value = 20 });
list.AddLast(new Node { value = 25 });
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  1. Call the function to calculate the variance of the values in the linked list:
main.cs
double varianceResult = variance(list);
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The variance() function takes the linked list as a parameter, calculates the mean of the values in the linked list, then calculates the sum of the squares of the difference between each value and the mean. Finally, it divides the sum of the squares by the number of values in the linked list to calculate the variance.

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