remove a node from the beginning of a linked list in go

To remove a node from the beginning of a linked list in Go, you can follow these steps:

1. Check if the linked list is empty. If it is empty, then there is no node to remove from the beginning.

2. If the linked list is not empty, then set the head of the linked list to the next node of the current head.

3. Set the value of the current head to nil to remove the node completely.

Here is the sample code that demonstrates the removal of node from the beginning of a linked list in Go:

main.go
type Node struct {
    value int
    next  *Node
}

type LinkedList struct {
    head *Node
}

func (l *LinkedList) removeFirstNode() {
    if l.head == nil {
        return
    }
    l.head = l.head.next
    l.head.value = nil
}
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In the above code, a linked list is represented using a LinkedList structure with a head field pointing to the first node of the linked list. The Node structure represents a node in the linked list, consisting of a value field and a next field pointing to the next node in the linked list.

The removeFirstNode method of the LinkedList structure removes the first node from the linked list. It first checks if the linked list is empty by checking if the head field is nil. If it is nil, then there is no node to remove from the beginning and the method returns. Otherwise, it sets the head field to the next node of the current head and sets the value field of the current head to nil, effectively removing the node from the linked list.