find the largest node in a linked list in javascript

One way to find the largest node in a linked list is by iterating through each node and keeping track of the maximum value seen so far. Here's an example implementation in JavaScript:

index.tsx
function findLargestNode(head) {
  let maxNode = head;
  let currentNode = head;

  while (currentNode !== null) {
    if (currentNode.value > maxNode.value) {
      maxNode = currentNode;
    }
    currentNode = currentNode.next;
  }

  return maxNode;
}
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The findLargestNode function takes the head node of the linked list as an argument and initializes two variables: maxNode and currentNode both to the head node. Then, it iterates through the linked list from the head node to the last one using a while loop.

Inside the loop, it compares the value of the currentNode with the value of the maxNode. If the value of the currentNode is greater than the value of the maxNode, it assigns the maxNode to point to the currentNode.

Finally, after the loop, it returns the maxNode, which should be the largest node in the linked list.