derive v(t) = 9.2 when t = 20 in matlab

To derive v(t) = 9.2 when t = 20 in MATLAB, we need to know the equation that governs v(t). Assuming that we have the equation, we can evaluate it at t = 20 using MATLAB's computation capabilities as follows:

main.m
% Define the equation that governs v(t)
% Example: v(t) = 2t^2 + 3t + 1
syms t;
vt = 2*t^2 + 3*t + 1;

% Evaluate v(t) at t = 20
t_val = 20;
v_val = double(subs(vt, t_val));
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The syms function is used to define a symbolic variable t that represents time. We then define vt as the equation that governs v(t) (in this case, v(t) = 2t^2 + 3t + 1).

The subs function is used to substitute t_val = 20 into vt. The double function is used to convert the symbolic result into a numeric value.

After running the code above, v_val should be equal to 9.2, which is the value of v(t) when t = 20.

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