find the volume of the region bounded between the planes x+y+2z=2 and 2x+2y+z=4 in the first octant. in matlab

To find the volume of the region bounded between the two planes in the first octant in MATLAB, you can use the triple integral. Here is an example code to calculate the volume:

main.m
syms x y z
f1 = x + y + 2*z - 2;
f2 = 2*x + 2*y + z - 4;

% Solve the equations for the intersection points
sol = solve(f1 == 0, f2 == 0, x, y, z);
sol_x = sol.x; % x values
sol_y = sol.y; % y values
sol_z = sol.z; % z values

% Define the limits of integration
x_limits = [0 sol_x];
y_limits = [0 sol_y];
z_limits = [0 sol_z];

% Calculate the volume using triple integral 
volume = integral3(@(x,y,z)1, x_limits, y_limits, z_limits);

disp("The volume of the region is " + volume)
483 chars
20 lines

Make sure to have the Symbolic Math Toolbox installed in MATLAB to perform symbolic computations. This code will give you the volume of the region bounded between the two planes in the first octant.

related categories

gistlibby LogSnag