write a program that accepts a year and determines whether the year is a leap year. use the mod function. the output should be the variable extra_day in matlab

To determine whether a year is a Leap year or not, one can use the following algorithm:

1. If the year is evenly divisible by 4, go to step 2. Otherwise, go to step 5.
2. If the year is evenly divisible by 100, go to step 3. Otherwise, go to step 4.
3. If the year is evenly divisible by 400, go to step 4. Otherwise, go to step 5.
4. The year is a leap year (it has 366 days).
5. The year is not a leap year (it has 365 days).

Based on the above algorithm, we can write the following Matlab code:

main.m
function extra_day = is_leap_year(year)

% Check if the year is divisible by 4
if mod(year, 4) == 0
    
    % Check if the year is divisible by 100
    if mod(year, 100) == 0
        
        % Check if the year is divisible by 400
        if mod(year, 400) == 0
            extra_day = 1; % Leap year
        else
            extra_day = 0; % Not leap year
        end
        
    else
        extra_day = 1; % Leap year
    end
    
else
    extra_day = 0; % Not leap year
end

end
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You can call the function by passing the year as a parameter and it will return 1 if it is a leap year, otherwise 0. For example, to check if the year 2020 is a leap year, we can call the function as follows:

main.m
is_leap_year(2020)
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This will return 1, indicating that 2020 is a leap year.

Note: the variable name "extra_day" might not be the most appropriate, as it suggests that the function returns the number of extra days in a leap year. It would be better to name it something like "is_leap" to indicate that it's a binary indicator (1 for leap year, 0 for not leap year).