find the surface area of a regular polygon inscribed in a cone in ruby

To find the surface area of a regular polygon inscribed in a cone, we need to determine the area of each face of the polygon and then sum them up.

Here's the code in Ruby:

main.rb
# Inputs
num_sides = 6   # number of sides of regular polygon
radius = 5      # radius of base of cone
height = 10     # height of cone

# Calculate side length and apothem of polygon
side_length = 2 * radius * Math.sin(Math::PI / num_sides)
apothem = radius * Math.cos(Math::PI / num_sides)

# Calculate area of each face of polygon
face_area = 0.5 * side_length * apothem

# Calculate surface area of polygon (and cone)
polygon_area = num_sides * face_area
cone_area = Math::PI * radius * (radius + Math.sqrt(height**2 + radius**2))

# Output result
puts "Surface area of regular polygon in cone: #{polygon_area} square units"
puts "Surface area of cone: #{cone_area} square units"
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In this code, we first define the number of sides of the regular polygon, the radius of the base of the cone, and the height of the cone as inputs. We then use the formulas for the side length and apothem of a regular polygon to calculate the area of each face of the polygon. Finally, we multiply the area of each face by the number of sides to get the total surface area of the polygon, and we also calculate the surface area of the cone itself. The outputs are printed to the console.

gistlibby LogSnag