find the largest node in a linked list in swift

To find the largest node in a linked list in Swift, we can traverse through the entire linked list and keep track of the current maximum node value. The steps involve creating a temporary variable to store the maximum value, and iterating through each node in the linked list, updating the maximum value if we find a node with a larger value.

Here is a sample implementation of a function to find the largest node in a singly linked list:

main.swift
class ListNode {
    var val: Int
    var next: ListNode?
    init(_ val: Int) {
          self.val = val
          self.next = nil
    }
}

func findLargestNode(head: ListNode?) -> Int {
    var current = head
    var maxVal = Int.min
    
    while current != nil {
        if current!.val > maxVal {
            maxVal = current!.val
        }
        current = current?.next
    }
    
    return maxVal
}
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This function takes the head node of the linked list as input, then initializes a variable "current" to the head node. It also initializes "maxVal" as the minimum integer value to ensure that the first node value is always greater than it.

We then traverse through each node in the linked list while updating the maximum value if we find a larger node. Finally, we return the maximum value found.