reduce array number that contain 10 numbers to only 2 numbers in swift

To reduce an array of 10 numbers to only 2 numbers in Swift, you can use a loop to iterate over the array, and an algorithm to perform the reduction. One possible algorithm is to find the maximum and minimum numbers in the array using the max() and min() functions, and then return them as a new array.

Here's an example implementation:

main.swift
let numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

var min = numbers[0]
var max = numbers[0]

// Find the maximum and minimum numbers in the array
for number in numbers {
    if number < min {
        min = number
    }
    if number > max {
        max = number
    }
}

// Return the maximum and minimum numbers as a new array
let result = [min, max]
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In this example, the numbers array contains 10 integers. The min and max variables are initialized to the first number in the array, and then updated in the loop as necessary. Finally, the result array is created with the minimum and maximum numbers as its elements, and returned as the output of the function.

Note that this implementation assumes that the array contains at least one number; if the array is empty, it will crash with an index-out-of-bounds error. You may want to add additional error-checking code as appropriate for your use case.