find the symmetric difference of two maps in typescript

index.ts
function symmetricDifference<T, U>(map1: Map<T, U>, map2: Map<T, U>): Map<T, U> {
  const result: Map<T, U> = new Map();

  // Iterate over the keys in map1
  for (const key of map1.keys()) {
    // If map2 does not have the same key, add it to the result
    if (!map2.has(key)) {
      result.set(key, map1.get(key) as U);
    }
  }

  // Iterate over the keys in map2
  for (const key of map2.keys()) {
    // If map1 does not have the same key, add it to the result
    if (!map1.has(key)) {
      result.set(key, map2.get(key) as U);
    }
  }

  return result;
}
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index.ts
const map1: Map<string, number> = new Map([['a', 1], ['b', 2], ['c', 3]]);
const map2: Map<string, number> = new Map([['b', 4], ['c', 3], ['d', 5]]);

const result: Map<string, number> = symmetricDifference(map1, map2);

console.log(result); // Output: Map { "a" => 1, "b" => 4, "d" => 5 }
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