find the symmetric difference of two maps in typescript

To find the symmetric difference of two maps in TypeScript, we can use the spread operator and a for...of loop.

Here's an example code snippet that demonstrates how to do this:

index.ts
function symmetricDifference<T, U>(map1: Map<T, U>, map2: Map<T, U>): Map<T, U> {
  const result: Map<T, U> = new Map();

  // Iterate over the keys in map1
  for (const key of map1.keys()) {
    // If map2 does not have the same key, add it to the result
    if (!map2.has(key)) {
      result.set(key, map1.get(key) as U);
    }
  }

  // Iterate over the keys in map2
  for (const key of map2.keys()) {
    // If map1 does not have the same key, add it to the result
    if (!map1.has(key)) {
      result.set(key, map2.get(key) as U);
    }
  }

  return result;
}
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Here's an example usage of the function:

index.ts
const map1: Map<string, number> = new Map([['a', 1], ['b', 2], ['c', 3]]);
const map2: Map<string, number> = new Map([['b', 4], ['c', 3], ['d', 5]]);

const result: Map<string, number> = symmetricDifference(map1, map2);

console.log(result); // Output: Map { "a" => 1, "b" => 4, "d" => 5 }
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In the example above, we have two maps map1 and map2. We use the symmetricDifference function to find the symmetric difference of these two maps and store the result in the result map. We then log the result map to the console which outputs Map { "a" => 1, "b" => 4, "d" => 5 }, which is the symmetric difference of map1 and map2.

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