find the smallest node in a linked list in go

To find the smallest node in a linked list in Go, you need to traverse the list and compare the value of each node with the current minimum value. If the value of a node is smaller than the minimum value, update the minimum value and the minimum node. Here is an example implementation:

main.go
type Node struct {
    Value int
    Next  *Node
}

func findSmallestNode(head *Node) *Node {
    if head == nil {
        return nil
    }

    minNode := head
    minValue := head.Value

    for node := head.Next; node != nil; node = node.Next {
        if node.Value < minValue {
            minNode = node
            minValue = node.Value
        }
    }

    return minNode
}
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In this implementation, we first check if the head of the list is nil. If it is, then the list is empty and we return nil. Otherwise, we initialize the minimum node and value to be the head of the list. We start iterating from the second node and compare its value with the current minimum value. If we find a node with a smaller value, we update the minimum node and value. Finally, we return the minimum node.