To perform percent conversion of a limiting agent in MATLAB, you need to know the stoichiometric ratios between reactants and products.
Here is a step-by-step approach to calculate the percent conversion of a limiting agent:
For example, we'll consider the reaction between hydrogen gas (H2) and oxygen gas (O2) to form water (H2O):
2H2 + O2 → 2H2O
Find the stoichiometric coefficients of the reactants and products in the balanced equation. In this case, 2 moles of H2 react with 1 mole of O2 to produce 2 moles of H2O.
Determine the number of moles of reactants present in the reaction. This value can be obtained from experimental data or given in the problem.
Identify the limiting agent, which is the reactant that is completely consumed first. To determine this, calculate the moles of different reactants and divide by their stoichiometric coefficients.
Once you have identified the limiting agent, calculate the theoretical number of moles of each product using the stoichiometry.
Finally, calculate the percent conversion of the limiting agent using the formula:
Percent Conversion = (Theoretical moles of limiting agent - Actual moles of limiting agent) / Theoretical moles of limiting agent * 100
Here's an example MATLAB code that calculates the percent conversion of a limiting agent:
main.m743 chars18 lines
Make sure to adjust the values of actual_h2_moles
and actual_o2_moles
according to your specific problem.
Note: This example assumes that H2 is the limiting agent. If O2 is the limiting agent, you need to adjust the calculations accordingly.
Remember to replace the coefficients and reactant data with your specific problem and adjust the formulas as needed.
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