plot (xy^3)/(1+y^2) = 8/5 in graph in matlab

To plot the equation (xy^3)/(1+y^2) = 8/5 in MATLAB, you can first solve for y to get:

main.m
y = sqrt((5*x)/(8 - 3*x))
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Then, you can create a range of x values, calculate the corresponding y values using the above equation, and plot them using the plot function in MATLAB. Here's an example code:

main.m
% Define the equation and solve for y
x = linspace(-10, 10, 1000);
y = sqrt((5*x)./(8 - 3*x));

% Plot the curve
plot(x, y, 'LineWidth', 2);
hold on;
plot(x, -y, 'LineWidth', 2);
grid on;
xlabel('x');
ylabel('y');
title('Plot of (xy^3)/(1+y^2) = 8/5');
legend('y > 0', 'y < 0');
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This will produce a graph with the x-axis ranging from -10 to 10, and the y-axis automatically scaled to fit the range of y values. The hold on command is used to plot both the positive and negative branches of the curve, and the grid on command adds a grid to the plot. The xlabel, ylabel, title, and legend commands are used to add labels and a legend to the plot.