To remove a node from the middle of a linked list in Rust, we need to find that node first. We can do this by traversing the linked list until we reach the middle node. Once we find the middle node, we can remove it by changing the previous node's next
pointer to skip over the middle node and point directly to the next node.
Here's an example Rust function that removes the middle node from a linked list:
main.rs1022 chars39 lines
In this code, we first declare a struct Node
that represents each node in the linked list. It contains the data (T
) and a next
pointer that points to the next node in the list.
The remove_middle_node
function takes a mutable reference to the head of the linked list (head: &mut Option<Rc<Node<T>>
) as input. It uses two pointers, one that moves through the list slowly (slow_ptr
) and one that moves through the list quickly (fast_ptr
).
We then traverse the list using these pointers and find the middle node. Once we have the middle node, we remove it by updating the next
pointer of the previous node to skip over the middle node and point directly to the next node.
Note that the Rc
type is used to create reference-counted pointers to the linked list nodes to ensure safe memory management.
gistlibby LogSnag