find the kth smallest key in a map in swift

To find the kth smallest key in a map (dictionary) in Swift, we first need to extract all the keys from the dictionary and sort them. We can then simply return the kth element from the sorted array. Here's the code:

main.swift
func findKthSmallestKey<K: Comparable, V>(in dictionary: [K: V], k: Int) -> K? {
    let keys = Array(dictionary.keys).sorted() // Extract and sort the keys
    if k > 0 && k <= keys.count { // Check if k is within range
        return keys[k-1] // Return kth smallest key
    }
    return nil // Return nil if k is out of range
}
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Here's an example usage:

main.swift
let myDictionary = ["a": 1, "c": 3, "b": 2, "e": 5, "d": 4]
if let kthSmallestKey = findKthSmallestKey(in: myDictionary, k: 3) {
    print("The 3rd smallest key is: \(kthSmallestKey)") // Output: The 3rd smallest key is: c
} else {
    print("Invalid k value")
}
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Note that the function returns an optional value in case the value of k is out of range.

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