make it a one-liner: `func lose(powerupactive: bool, touchingeagle: bool) -> bool { !powerupactive && touchingeagle }` in swift

You can make the function lose a one-liner using the ternary operator in Swift. Here's how you can achieve that:

main.swift
func lose(powerupactive: Bool, touchingeagle: Bool) -> Bool { !powerupactive && touchingeagle }
96 chars
2 lines

Note that the above code is already a one-liner. The function lose returns !powerupactive && touchingeagle which is a boolean value.

If you need a separate one-liner expression that assigns the result to a variable, you can use the ternary operator as follows:

main.swift
let result = !powerupactive && touchingeagle ? true : false
60 chars
2 lines

This assigns true to result if !powerupactive && touchingeagle evaluates to true, otherwise it assigns false.

Let me know if you need any further assistance!