ixed beam by two supports and concrete load calculate shear force diagram and bending moment diagram and deflection in matlab

main.m
% Fixed beam with two supports and concrete load

% Define constants
L = 10; % Length of the beam (in meters)
w = 5; % Uniformly distributed load (in kN/m)
E = 200 * 10^9; % Young's Modulus of the beam material (in Pa)
I = 10^-4; % Moment of inertia of the beam (in m^4)

% Create the symbolic variable x
syms x;

% Define the functions for load, shear force, bending moment, and deflection
w_x = @(x) w; % Uniformly distributed load

V_x = @(x) w*x - w*x^2/(2*L); % Shear force function
M_x = @(x) w*x^2/2 - w*x^3/(6*L); % Bending moment function

M_max = max(abs(M_x(x))); % Maximum bending moment

delta_x = w*x^4 / (24*E*I) * (L^3 - 2*L*x^2 + x^3); % Deflection function

% Plot the shear force diagram
figure;
fplot(V_x, [0, L], 'LineWidth', 1.5);
title('Shear Force Diagram');
xlabel('Position along the beam (m)');
ylabel('Shear Force (kN)');
grid on;

% Plot the bending moment diagram
figure;
fplot(M_x, [0, L], 'LineWidth', 1.5);
title('Bending Moment Diagram');
xlabel('Position along the beam (m)');
ylabel('Bending Moment (kN.m)');
grid on;

% Display the maximum bending moment
disp(['Maximum Bending Moment: ', num2str(M_max), ' kN.m']);

% Calculate and display the deflection at the midpoint of the beam
midpoint = L/2;
deflection = double(subs(delta_x, x, midpoint));
disp(['Deflection at midpoint: ', num2str(deflection), ' meters']);
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In this MATLAB code, a fixed beam with two supports and a concrete load is analyzed to calculate the shear force diagram, bending moment diagram, and deflection. The beam is subjected to a uniformly distributed load. The code defines the load, shear force, bending moment, and deflection functions, and then plots the shear force diagram and bending moment diagram. It also calculates the maximum bending moment and the deflection at the midpoint of the beam.

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