find the volume of a pyramid in rust

To find the volume of a pyramid in Rust, we need to follow a formula which uses the width, length, and height of the pyramid. We can implement this formula in Rust using a function as follows:

main.rs
fn pyramid_volume(width: f32, length: f32, height: f32) -> f32 {
    let base_area = width * length;
    return (base_area * height) / 3.0;
}
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This function takes in three arguments, width, length, and height, and returns the volume of the pyramid.

To call this function we can use the following example:

main.rs
fn main() {
    let width = 5.0;
    let length = 6.0;
    let height = 8.0;

    let volume = pyramid_volume(width, length, height);

    println!("The volume of the pyramid is: {}", volume);
}
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Here we have initialized the values of width, length, and height, and then passed these values to the pyramid_volume function. The function calculates the volume of the pyramid based on these values and returns it to the volume variable. Finally, we print the result using the println! macro.