find the volume of a regular polygon inscribed in a sphere in rust

To find the volume of a regular polygon inscribed in a sphere, we can use the formula:

V = (2/3) * n * r^3 * sin(2*pi/n)

where n represents the number of sides in the regular polygon, r is the radius of the sphere, and pi is the mathematical constant pi.

Here is the implementation of this formula in Rust:

main.rs
use std::f64::consts::PI;

fn volume_of_inscribed_polygon(n: i32, r: f64) -> f64 {
    let sin_val = (2.0 * PI / n as f64).sin();
    return (2.0 / 3.0) * (n as f64) * r.powi(3) * sin_val;
}

fn main() {
    let n = 6; // number of sides of polygon
    let r = 1.0; // radius of sphere
    let volume = volume_of_inscribed_polygon(n, r);
    println!("The volume of inscribed polygon is {}", volume);
}
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In this code, we define a function volume_of_inscribed_polygon that takes in two arguments n and r and returns the volume of the inscribed polygon. Inside the function, we compute the sin value using the formula and then use it to compute the volume using the formula. Finally, we call this function inside the main function and print the volume.